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4 g hydrogen is mixed with 11.2 litre of...

`4 g` hydrogen is mixed with 11.2 litre of He at (STP) in a container of volume 20 litre. If the final temperature is `300 K`, find the pressure.

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`4g` hydrogen `=2` moles hydrogen
`11.2` litre He at `STP = (1)/(2)` mole of He
`P = P_(H) + P_(He) = (n_(H) + n_(He))(RT)/(V)`
`= (2 + (1)/(2))(8.31 xx (300))/((20 xx 10^(-3))) = 3.12 xx 10^(5) N // m^(2)`
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