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If an air bubbles rises from the bottom of a mercury tank to the top its volume becomes `1(1)/(2)` times. When normal pressure is `76 cm` of `Hg` then the depth of the `Hg` tank is

A

`38 cm`

B

`123 cm`

C

`76 cm`

D

`49 cm`

Text Solution

Verified by Experts

The correct Answer is:
A
`P_(1)V_(1) = P_(2)V_(2) , (H + h)V_(1) = HV_(2)`
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