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Two identical containers connected by a ...

Two identical containers connected by a fine caillary tube contain air at `N.T.P` if one of those containers is immersed in pure water, boiling under noramal pressure then new pressure is

A

`76 cm` of `Hg`

B

`152 cm` of `Hg`

C

`57 cm` of `Hg`

D

`87.76 cm` of `Hg`

Text Solution

Verified by Experts

The correct Answer is:
D
`(P_(1)V_(1))/(T_(1)) = `(P_(1)V_(1))/(T_(1)) = P_(1)((V_(1))/(T_(1)) + (V_(1))/(T_(1)))`
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