During an experiment an idea gas is found to obey an additional gas law VT = constant. The gas is initially at temperature `T` and pressure `P`. When it is heated to the temperature `2T`, the resulting pressure is

Options

A. `2P`
B. `P//2`
C. `4P`
D. `P//4`

Answer

C

Explanation

`(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2)) , (P_(1))/(P_(2)) = (T_(1))/(T_(2))(V_(2))/(V_(1))`, Given `V prop (1)/(T)`
`:. (V_(2))/(V_(1)) = (T_(1))/(T_(2))` and `(P_(1))/(P_(2)) = (T_(1))/(T_(2)) xx (T_(1))/(T_(2))`