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An ideal gas is initially at temperature...

An ideal gas is initially at temperature T and volume V. Its volume is increased by `DeltaV` due to an increase in temperature `DeltaT,` pressure remaining constant. The quantity `delta=(DeltaV)/(VDeltaT)` varies with temperature as

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
C
`(DeltaV)/(V) = (DeltaT)/(T) :. Lambda(1)/(L)`
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