In Boyles experiment for a given gas at different temperature the graph drawn between pressure and density are straight lines as shown then

Options

A. `T_(1) gt T_(2)`
B. `T_(2) gt T_(1)`
C. `T_(1) = T_(2)`
D. `T_(1)^(3) = T_(2)`

Answer

A

Explanation

P = constant , At constant pressure `d prop (1)/(T)` from graph `d_(2) gt d_(1)` then `T_(2) lt T_(1)`