Two identical container each of volume `V_(0)` are joined by a small pipe. The containers contain identical gases at temperature `T_(0)` and pressure `P_(0)`. One container is heated to temperature `2T_(0)` while maintaining the other at the same temperature. The common pressure of the gas is `P` and `n` is the number of moles of gas in container at temperature `2T_(0)`.

Options

A. `P = 2P_(0)`
B. `P = (4)/(3)P_(0)`
C. `n = (2P_(0)V_(0))/(3RT_(0))`
D. `n = (2P_(0)V_(0))/(2RT_(0))`

Answer

C

Explanation

`n_(1) + n_(2) = n_(1)^(1) + n_(2)^(1)`
`(P_(0)V_(0))/(RT_(0)) + (P_(0)V_(0))/(RT_(0)) = (PV_(0))/(RT_(0)) + (PV_(0))/(R2T_(0))`
`(2P_(0)V_(0))/(RT_(0)) = (PV_(0))/(RT_(0))((3)/(2)) rArr P = (4P_(0))/(3)`
From ideal gas equation `PV = nRT`
`(4P_(0))/(3)V_(0) = n_(2)^(1)R(2T_(0))`