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The displacement of a particle in SHM is...

The displacement of a particle in `SHM` is `x = 3sin (20 pit) +4 cos(20pit)cm`. Its amplitude of oscillation is

A

`3cm`

B

`4cm`

C

`5cm`

D

`25cm`

Text Solution

Verified by Experts

The correct Answer is:
C
`A = sqrt(A_(1)^(2)+A_(2)^(2))`
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Knowledge Check

  • The displacement of a particle is given by x = 3 sin ( 5 pi t) + 4 cos ( 5 pi t) . The amplitude of particle is

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    `10pi m//s`
    B
    `-2pi^(2)m//s^(2)`
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    D
    `4pi^(2)m//s^(2)`

  • The displacement of a particle executing S.H.M. is x = 5 sin (20 pit ). Then its frequency will be

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