The displacement of a particle in SHM is...

The displacement of a particle in `SHM` is `x = 3sin (20 pit) +4 cos(20pit)cm`. Its amplitude of oscillation is

A

`3cm`

B

`4cm`

C

`5cm`

D

`25cm`

Text Solution

Verified by Experts

The correct Answer is:

C

`A = sqrt(A_(1)^(2)+A_(2)^(2))`

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