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The displacement of a particle in SHM is...

The displacement of a particle in `SHM` is `x = 3sin (20 pit) +4 cos(20pit)cm`. Its amplitude of oscillation is

A

`3cm`

B

`4cm`

C

`5cm`

D

`25cm`

Text Solution

Verified by Experts

The correct Answer is:
C
`A = sqrt(A_(1)^(2)+A_(2)^(2))`
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Knowledge Check

  • The displacement of a particle is given by x = 3 sin ( 5 pi t) + 4 cos ( 5 pi t) . The amplitude of particle is

    A
    `3`
    B
    `4`
    C
    `5`
    D
    `7`

  • The displacement of a particle performing S.H.M. is x = 0.1 sin (5pit)+0.4cos(5pit)m . Then acceleration of the particle at 0.1 s is

    A
    `10pi m//s`
    B
    `-2pi^(2)m//s^(2)`
    C
    `-2.5 pi^(2)m//s^(2)`
    D
    `4pi^(2)m//s^(2)`

  • The displacement of a particle executing S.H.M. is x = 5 sin (20 pit ). Then its frequency will be

    A
    `20pi` Hz
    B
    20 Hz
    C
    10 Hz
    D
    10`pi` Hz
    • NARAYNA-OSCILLATIONS-LEVEL -I (C.W)
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    2. A particle moves according to the law, x=acos(pit//2). . What is the d...

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    8. A body executing SHM has a maximum velocity of 1ms^(-1) and a maximum ...

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    9. The time period of oscillation of a particle that executes SHM is 1.2s...

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    10. A particle executes SHM with a amplitude 0.5 cm and frequency 100s^(-1...

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    11. For a body in SHM the velocity is given by the relation V = sqrt(144-1...

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    13. The maximum velocity a particle, executing simple harmonic motion with...

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    17. A simple harmonic oscillator is of mass 0.100 kg. It is oscillating wi...

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    18. A small body of mass 10 grams is making harmonic oscillations along a ...

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    19. At what displacement is the KE of a particle performing SHM of amplitu...

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