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The displacement of a particle executing...

The displacement of a particle executing `SHM` at any time `t` (Seconds) is `x =0.01sin 100pi (t = 0.005)` then its time period will be

A

`0.2s`

B

`0.1s`

C

`0.06s`

D

`0.02s`

Text Solution

Verified by Experts

The correct Answer is:
D
`x = A sin (omega t+phi), omega = (2pi)/(T)`
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