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The time period of oscillation of a part...

The time period of oscillation of a particle that executes `SHM` is `1.2s`. The time starting from mean position at which its velocity will be half of its velocity at mean position is

A

`0.1s`

B

`0.2s`

C

`0.4s`

D

`0.6s`

Text Solution

Verified by Experts

The correct Answer is:
A
`V = (V_(max))/(2) rArr x =+-(sqrt(3)A)/(2), x = A cos ((2pi)/(T)t)`
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