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Two springs of force constants 1000N//m ...

Two springs of force constants `1000N//m` and `2000N//m` are stretched by same force. The ratio of their respective potential enegries is

A

`2:1`

B

`1:2`

C

`4:1`

D

`1:4`

Text Solution

Verified by Experts

The correct Answer is:
A
`P.E. = (1)/(2)Kx^(2)`
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