A pendulum of length `L` swings from rest to rest `n` times in one second. The value of acceleration due to gravity is

Options

A. `4pi^(2)n^(2)L`
B. `2pi^(2)n^(2)L`
C. `pi^(2)n^(2)L`
D. `(pi^(2)n^(2)L)/(2)`

Answer

C

Explanation

`f = (1)/(2pi) sqrt((g)/(L)) = (n)/(2)`