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A simple pendulam has time period T(1) w...

A simple pendulam has time period `T_(1)` when on the earth's surface and `T_(2)` when taken to a height `R` above the earth's surface where `R` is the radius of the earth. The value of `(T_(2))/(T_(1))` is-

A

`2`

B

`1`

C

`sqrt(2)`

D

`4`

Text Solution

Verified by Experts

The correct Answer is:
A
`T = 2pi sqrt((l)/(g)), g_(h) = (g)/((1+(h)/(R))^(2))`
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