Two particles undergo `SHM` along the same line with the same time period `(T)` and equal amplitude `(A)`. At a particular instant one is at `x =- A` and the other is at `x =0`. If they start moving in the same direction then they will cross each other at

(i) `t = (4T)/(3)` (ii) `t = (3T)/(8)` (iii) `x = (A)/(2)` (iv) `x = (A)/(sqrt(2))`

Options

A. only i, ii, are correct
B. only i,iv are correct
C. only ii,iii are correct
D. only ii,iv are correct

Answer

D

Explanation

Time after which they meet `t = (T)/(4) +(T)/(8), t' = (T)/(8), x = A cos (omegat)`