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A simple pendulum executing SHM in a str...

A simple pendulum executing `SHM` in a straight line has zero velocity at 'A' and 'B' whose distances form 'O' in the same line `OAB` are 'a' and 'b'. If the velocity half wat between them is 'v' then its time period is

A

`(pi(b+a))/(v)`

B

`pi((b-a)/(v))`

C

`((b+a)/(2v))`

D

`((b-a)/(2v))`

Text Solution

Verified by Experts

The correct Answer is:
B
`v_(mean) = A omega, A = ((b-a)/(2))`
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