Home
Class 11
PHYSICS
A pendulum of mass m and length L is con...

A pendulum of mass `m` and length `L` is connected to a spring as shown in figure. If the bob is displaced slightly from its mean position and released, it performs simple harmonic motion. The angular frequency of the oscillation of bob is

A

`sqrt((g)/(L))`

B

`sqrt((Kh^(2)+mgL)/(mL^(2)))`

C

`sqrt(3g)/(L)`

D

`sqrt((Kh^(2))/(mL^(2)))`

Text Solution

Verified by Experts

The correct Answer is:
B

`tau_(rest) =- T alpha` For small angular displacement `theta mgl sin theta = kyh =- I alpha sin theta = theta, tan theta = (y)/(h) = theta`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • OSCILLATIONS

    NARAYNA|Exercise NCERT BASED QUESTIONS|1 Videos
  • OSCILLATIONS

    NARAYNA|Exercise MULTIPLE ANSWER QUESTIONS|23 Videos
  • OSCILLATIONS

    NARAYNA|Exercise LEVEL -II (C.W)|36 Videos
  • NEWTONS LAWS OF MOTION

    NARAYNA|Exercise PASSAGE TYPE QUESTION|6 Videos
  • PHYSICAL WORLD

    NARAYNA|Exercise C.U.Q|10 Videos

Similar Questions

Explore conceptually related problems

If the frequency of oscillation of a pendulum in simple harmonic motion is n, then frequency of pendulum whose length becomes four times is

A pendulum bob of mass m and length L is released from angle theta with the vertical. Find (a) the speed of the bob at the bottom of the swing and (b) tension in the string at that time

Knowledge Check

  • A body of mass m is suspended from three springs as shown in figure. If mass m is displaced slightly then time period of oscillation is

    A
    `2pi sqrt((m)/(3K))`
    B
    `2pi sqrt((3m)/(2K))`
    C
    `2pi sqrt((2m)/(3K))`
    D
    `2pi sqrt((3K)/(m))`
  • A horizontal rod of mass m and length L is pivoted at one end The rod's other end is supported by a spring of force constant k. The rod is displaced by a small angle theta from its horizontal equilibrium position and released. The angular frequency of the subsequent simple harmonic motion is

    A
    `sqrt((3k)/(m))`
    B
    `sqrt((k)/(3m))`
    C
    `sqrt((3k)/(m)+(3g)/(2L))`
    D
    `sqrt((k)/(m))`
  • The bob of a simple pendulum of length L, is displaced through 90^(@) , from its mean position and then released. What will be the tension in the string when the bob of mass m will be at its lowest position?

    A
    mg
    B
    3 mg
    C
    2 mg
    D
    6 mg
  • Similar Questions

    Explore conceptually related problems

    In the situation shown, a pendulum bob of mass m and length L is taken aside and released from rest from the angular position theta as shown. If the mass takes time t to reach the lowest point. Find the magnitude of impulse of tension (in the string) on mass m from time t=0 to t.

    The bob of a simple pendulum of length L, is displaced through 90^(@) , from its mean position and then released. What will be the tension in the string when the bob of mass m will be its lowest position ?

    Three springs of each force constant k are connected as shown figure. Point mass m is slightly displaced to compress A and released. Time period of oscillation is

    A simple pendulum of mass m and length L is held in horizontal position. If it is released from this position, then find the angular momentum of the bob about the point of suspension when it is vertically below the point of suspension.

    The acceleration of a simple harmonic oscillator is 1 m//s^(2) when its displacement from mean position is 0.5 m. Then its frequency of oscillation is