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A simple pendulum of length 4.9m is imme...

A simple pendulum of length `4.9m` is immersed in a liquid of density `rho =0.4 kg//m^(3)`. Then the time period of pendulum is (density of bob `=0.8 kg//m^(3))`

A

`pi s`

B

`3pi s`

C

`2 pi s`

D

`pi//2s`

Text Solution

Verified by Experts

The correct Answer is:
A
`T = 2pi sqrt((l)/(g_(eff)))` where `g_(eff) = g (1-(rho)/(sigma))`
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