In the previous problem, if tunnel is dug along a chord, find time period.

Options

A. `1600 pi`
B. `100 pi`
C. `2pi`
D. `10 pi`

Answer

A

Explanation

Acceleration of the body, `a = (F)/(m)`
`=(-GM)/(R^(3)) (x sin theta)`
Substituting `(GM)/(R^(2)) = g` and `x sin theta = y`, we get
`a =- (g)/(R )y =- omega^(2)y`