A block of mass `M` is connected to a spring of force constant `k` and is placed on a smopth horizontal surface. The block is displaced and compressed the spring by ''A''. The block is left free to move form this position, when the block is at distance `A//2` form mean position to collides elastically with the identical block. tme to be taken by block to move from exterme position to mean position is....

Options

A. `2pisqrt((M)/(K))`
B. `(pi)/(2) sqrt((M)/(K))`
C. `(pi)/(2) sqrt((2M)/(K))`
D. `(5pi)/(6) sqrt((M)/(K))`

Answer

D

Explanation

`PQ = QO, t_(PO) =t_(PQ) +t_(QO)`,
`t_(PQ) = (T)/(6) +t_(QO)…(1), T =2pi sqrt((M)/(K)) …..(2)`