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A small block oscillates back and forth ...

A small block oscillates back and forth on a smooth concave surface of radius R. Find the time period of small oscillation.

A

`2pi sqrt((R )/(g))`

B

`2sqrt((R )/(g))`

C

`pi sqrt((R )/(g))`

D

`sqrt((R )/(g))`

Text Solution

Verified by Experts

The correct Answer is:
A

Let `theta = (x)/(R ), F_(res) = mg sin theta, sin rarr` small
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