A `L`-shaped bar of mass `M` is pivoted at one of its end so that it can freely rotate in a vertical plane as shwon. If it is slightly displaced from its equilibrium position then the frequency of oscillation is…….

Options

A. `(1)/(2pi) sqrt((g/(L)((3sqrt(10))/(4))`
B. `(1)/(2pi) sqrt((g)/(L)((sqrt(10))/(4)))`
C. `(1)/(2pi) sqrt((g)/(L)(sqrt(2)))`
D. `(1)/(2pi) sqrt((g)/(2L))`

Answer

A

Explanation

Concept of physical pendulum `f = (1)/(2pi) sqrt((mgl)/(I))` where `l =` length between point of suspension and centre of mass, `I =` moment of inertia about `A`
`rArr l = (L)/(4) sqrt(10), I = (ML^(2))/(3)`