A particle pendulum is positioned such that is centre of gravity is vertically above suspension point. From that position the pendulum started moving tward the stable equilibroum and passed it with an angular velocity `omega`. By neglecting the friction at point of suspension, the period of small oscillations of the pendulum is

Options

A. `(2pi)/(omega)`
B. `(4pi)/(omega)`
C. `(pi)/(omega)`
D. `(5pi)/(omega)`

Answer

B

Explanation

From law of conservation of energy
`mg (2l) = (1)/(2) I omega^(2) ………..(1)`
Time period: `T = 2pi sqrt((I)/(mgl)) …………….(2)`
Solve (1) & (2), to get `T = ?`