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The distabce travelled in a time, t by a...

The distabce travelled in a time, t by a particle moving along `x`-axis according to an equation `x = A cos omegat` is given by `S = nA +S_(0)`, when time `t` can be written as `t =n((T)/(4)) +t_(0)` such that `t_(0) lt T//4` and distance travelled in that `t_(0)` is `S_(0)`.
The distance `S` is, when 'n' is even number:

A

`S = A [(n+1)-cos (omegat +(npi)/(2))]`

B

`S = A[(n+1)-cos (omegat-(npi)/(2))]`

C

`S =A [A +sin (omegat -(npi)/(2))]`

D

`S = A [(n+1)-sin (omegat -(npi)/(2))]`

Text Solution

Verified by Experts

The correct Answer is:
B
`S = nA +S_(0) , S_(0) = A - x_(0) , x_(0) = A cos wt_(0)`
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Knowledge Check

  • The distabce travelled in a time, t by a particle moving along x -axis according to an equation x = A cos omegat is given by S = nA +S_(0) , when time t can be written as t =n((T)/(4)) +t_(0) such that t_(0) lt T//4 and distance travelled in that t_(0) is S_(0) . The distance S is, when 'n' is odd number.

    A
    `S =A [(n+1) -cos (omegat+(npi)/(2))]`
    B
    `S = A[(n+1)-cos (omegat-(npi)/(2))]`
    C
    `S = A[n +sin (omegat -(npi)/(2))]`
    D
    `S = A [(n+1)-sin (omegat-(npi)/(2))]`

  • If the distance s travelled by a particle in time t is s=a sin t +b cos 2t , then the acceleration at t=0 is

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    `a`
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    `-a`
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    `4b`
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    `-4b`

  • The distance s travelled by a particle moving on a straight line in time t sec is given by s=2t^(3)-9t^(2)+12t+6 then the initial velocity of the particle is

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    6
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    11

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