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A uniform dics of mass m and radius R=(8...


A uniform dics of mass m and radius `R=(80)/(23pi^2)`m is pivoted smoothly at `P`. If a uniform ring of mass `m` and radius `R` is welded at the lowest point of the disc, find the period of `SHM` of the system (disc `+` ring). (in seconds)

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The correct Answer is:
2

`T = 2pi sqrt((I)/(Mgr)): I = I_("disc") + I_("rind")`

`= (3mR^(2))/(2) + 10 mR^(2) M = 2m : r = 2R`
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