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A seconds pendulum is suspended form the...

A seconds pendulum is suspended form the roof of a lift. If the lift is moving up with an acceleration `9.8 m//s^(2)`, its time period is

A

`1s`

B

`sqrt(2)`

C

`(1)/(sqrt(2))s`

D

`2sqrt(2)s`

Text Solution

Verified by Experts

The correct Answer is:
B
`T = 2pi sqrt((l)/(g+a))`
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