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A second pendulum is shifted from a plan...

A second pendulum is shifted from a plane where `g = 9.8 m//s^(2)` to another place where `g = 9.82 m//s^(2)`. To keep period of oscillation constant its length should be

A

decreased by `(2)/(pi^(2))cm`

B

increased by `(2)/(pi^(2))cm`

C

increased by `(2)/(pi)cm`

D

decreased by `(2)/(pi)cm`

Text Solution

Verified by Experts

The correct Answer is:
B
`Deltal = (Deltag)/(pi^(2))`
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