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Three simple pendulums have length of st...

Three simple pendulums have length of strings `49cms, 48 cms` and `47 cms` with diameters of the bobs `2cms, 4 cm` and `6 cm` respectively. Then their periods are in the ratio

A

`1:1:1`

B

`1:2:3`

C

`3:2:1`

D

`51:52:53`

Text Solution

Verified by Experts

The correct Answer is:
A
`T alpha sqrt(l)` where `l` is length of the pendulum from point of suspension to centre of the bob `l = x +r`
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