Home
Class 11
PHYSICS
The period of a simple pendulum is found...

The period of a simple pendulum is found to be increased by `50%` when the length of the pendulum is increased by `0.6m`. The initial length is

A

`0.16 m`

B

`0.32m`

C

`0.48m`

D

`0.60m`

Text Solution

Verified by Experts

The correct Answer is:
C
`(T_(2))/(T_(1)) = sqrt((l+x)/(l))`
Promotional Banner

Topper's Solved these Questions

  • OSCILLATIONS

    NARAYNA|Exercise DAMPED AND FORCED OSCILLATIONS|2 Videos

  • OSCILLATIONS

    NARAYNA|Exercise LEVEL-II (H.W)|1 Videos

  • OSCILLATIONS

    NARAYNA|Exercise OSCILLATIONS DUE TO A SPRING|13 Videos

  • NEWTONS LAWS OF MOTION

    NARAYNA|Exercise PASSAGE TYPE QUESTION|6 Videos

  • PHYSICAL WORLD

    NARAYNA|Exercise C.U.Q|10 Videos

Similar Questions

Explore conceptually related problems

The time period of a simple pendulum can be increased by

Time period of simple pendulum increase with

If length of pendulum is increased by 2%. The time period will

The time period of a simple pendulum of length 9.8 m is

If the length of simple pendulum is increased by 21%, then its time period is

If the length of a simple pendulum is increased by 2%, then the time period

The period of a simple pendulum is double, when its length is increased by 1.2 m. The original length of the simple pendulum is