Home
Class 11
PHYSICS
If the length of a seconds pendulum is i...

If the length of a seconds pendulum is increased by `2%` then in a day the pendulum

A

loses `764s`

B

loses `964 s`

C

gains `764 s`

D

loses `864 s`

Text Solution

Verified by Experts

The correct Answer is:
D
loss or gain of time per second is
`(T_(2)-T_(1))/(T_(1)) = (sqrt(l_(2))-sqrt(l_(1)))/(sqrt(l_(1)))`
Promotional Banner

Topper's Solved these Questions

  • OSCILLATIONS

    NARAYNA|Exercise DAMPED AND FORCED OSCILLATIONS|2 Videos

  • OSCILLATIONS

    NARAYNA|Exercise LEVEL-II (H.W)|1 Videos

  • OSCILLATIONS

    NARAYNA|Exercise OSCILLATIONS DUE TO A SPRING|13 Videos

  • NEWTONS LAWS OF MOTION

    NARAYNA|Exercise PASSAGE TYPE QUESTION|6 Videos

  • PHYSICAL WORLD

    NARAYNA|Exercise C.U.Q|10 Videos

Similar Questions

Explore conceptually related problems

The length of a second pendulum is

If the length of a simple pendulum is increased by 2%, then the time period

If the length of seconds pendulum is decreased by 1%, the gain or lose time per day by the pendulum will be

If the length of simple pendulum is increased by 21%, then its time period is

If the length of a second's pendulum is decreased by 0.1 %, the pendulum gain or lose per day will be

Effective length of a seconds pendulum is about.

If the length of a second's pendulum is increased by 1% , how many seconds will it loss or gain in a day ?