Home
Class 11
PHYSICS
Two simple pendulums of length 100m and ...

Two simple pendulums of length `100m` and `121m` start swinging together. They will swing together again after

A

the longer pendulum makes `10` oscillations

B

the shorter pendulum makes `10` oscillations

C

the longer pendulum makes `11` oscillations

D

the shorter pendulum makes `20` oscillations

Text Solution

Verified by Experts

The correct Answer is:
A

`nT_(s) = (n-1)T_(1)`
Promotional Banner

Topper's Solved these Questions

  • OSCILLATIONS

    NARAYNA|Exercise DAMPED AND FORCED OSCILLATIONS|2 Videos
  • OSCILLATIONS

    NARAYNA|Exercise LEVEL-II (H.W)|1 Videos
  • OSCILLATIONS

    NARAYNA|Exercise OSCILLATIONS DUE TO A SPRING|13 Videos
  • NEWTONS LAWS OF MOTION

    NARAYNA|Exercise PASSAGE TYPE QUESTION|6 Videos
  • PHYSICAL WORLD

    NARAYNA|Exercise C.U.Q|10 Videos

Similar Questions

Explore conceptually related problems

Two simple pendulums of lengths 1.44 m and 1 m start swinging together. After how many vibrations will they again start swinging together

Two pendulums of lengths 1.69m and 1.44m start swinging togther. After how many vibrations will they again start swinging togther?

Two simple pendulums of lengths 100 cm and 144cm start oscillating together at time t = 0. The minimum time after which they swing together is (take g=pi^(2)ms^(-2) )

Two simple pendulums of lengths 1.21m and 1.00 m start swinging at the same time from a location. After how much time, they will be (a) out of phase and (b) in phase again? Take g=10m//s^(2) .

Two simple pendulams of lengths 1 and 1.1 m rerspectively start swinging together with the same aplitude. Find the number of swings executed by the longer pendulam before again swing together. [Hint: The longer pendulam will swing more slowely than the shorter. Both will agin begain together after the faster pendulam gains by a complete number of oscillations. Let n be the number of oscillations the longer one makes before they again begain together. therefore (n+x) T_(1)=nT_(2) , where x is the number of oscillations by which the first gains over the second.]

Two simple pendulums of length 1m and 1.21 m are started oscillating from some position. Find the minimum time (in second) after which they again start from same position.

Two simple pendulum A and B of lengths 1.69m and 1.44m start swinging at the time from a location where acceleration due to gravity is 10ms^(-1) . Answer the following question. After how much time, the two pendulums will be in phase again ?

Two simple pendulum A and B of lengths 1.69m and 1.44m start swinging at the time from a location where acceleration due to gravity is 10ms^(-1) . Answer the following question. What will be the apporximate gain or loss ot time by pendulum A in a day with respect to second's pendulum ?

Two simple pendulum A and B of lengths 1.69m and 1.44m start swinging at the time from a location where acceleration due to gravity is 10ms^(-1) . Answer the following question. How many vibratinos pendulum A will compelte when it will be out of phase with B ?

Two simple pendulum of length l and 16l are released from the same phase together. They will be at the same time phase after a minimum time.