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Calculate the binding energy per nucleo...

Calculate the binding energy per nucleon of `._(20)^(40)Ca`. Given that mass of `._(20)^(40)Ca` nucleus `= 39.962589 u`, mass of proton `= 1.007825 u`. Mass of Neutron `= 1.008665 u` and `1 u` is equivalent to `931 MeV`.

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To calculate the binding energy per nucleon of the calcium-40 nucleus, we will follow these steps: ### Step 1: Identify the values - Mass of the calcium-40 nucleus, \( m_{\text{Ca}} = 39.962589 \, u \) - Mass of a proton, \( m_p = 1.007825 \, u \) - Mass of a neutron, \( m_n = 1.008665 \, u \) - Atomic mass number \( A = 40 \) - Number of protons \( Z = 20 \) ...
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