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Obtain the amount of .^60Co necessary to...

Obtain the amount of `.^60Co` necessary to provide a radioactive source of `8.0 Ci` strength. The half-life of `.^60Co` is `5.3` years?

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Half-life of `.^(60)._(27)Co=5.3` years
`=5.3xx365xx24xx60xx60S=5.3xx3.15xx10^(7)s`
Now `'x' gm` of `.^(60)._(27)Co`contains `(10^(-3))/(60)k`- mole
`=(xxx10^(-3))/(60)xx6.025xx10^(6)`
`N=0.1004x xx10^(23)=1.004x xx10^(22)` atoms
Required strength of `.^(60)._(27)Co=8 mCi`
`=8xx10^(-3)xx3.7xx10^(10)dis//s`
We know that, decay rate `(R )=lambdaN`
`N=(R )/(lambda)=(8xx3.7xx10^(7))/(0.693//T_(1//2))`
`(29.6xx10^(7))/(0.693)xx5.3xx3.15xx10^(7)=713.0909xx10^(14)`
`1.004x xx10^(22)=713.0909xx10^(14)`
`x=710.2499xx10^(-8) kg = 7.1xx10^(-6)g`
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