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.(92)U^(238)rarr.(82)Pb^(206)+8.(2)^(4)H...

`._(92)U^(238)rarr._(82)Pb^(206)+8._(2)^(4)He`. The number of `beta` particles releaased in this reaction is

A

`6`

B

`3`

C

`1`

D

`10`

Text Solution

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The correct Answer is:
A
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