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When .90 Th^228 transforms to .83 Bi^212...

When `._90 Th^228` transforms to `._83 Bi^212`, then the number of the emitted `alpha-`and `beta-`particle is, respectively.

A

`4alpha, 7 beta`

B

`4 alpha, 1 beta`

C

`4 alpha`

D

`7 beta`

Text Solution

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The correct Answer is:
C
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