The number of protons, electrons and neutrons in the nucleus of `""_(13)Al^(27)` is

Options

A. `13,13,14`
B. `13,0,14`
C. `14,14,13`
D. `14,0,13`

Answer

To determine the number of protons, electrons, and neutrons in the nucleus of the isotope \( _{13}^{27}\text{Al} \) (Aluminum-27), we can follow these steps:

### Step 1: Identify the mass number and atomic number
- The notation \( _{13}^{27}\text{Al} \) indicates that the mass number (A) is 27 and the atomic number (Z) is 13.
- The atomic number represents the number of protons in the nucleus.

### Step 2: Determine the number of protons
- The number of protons is equal to the atomic number (Z).
- Therefore, the number of protons in Aluminum-27 is:
\[ \text{Number of protons} = Z = 13 \]

### Step 3: Determine the number of neutrons
- The number of neutrons can be calculated using the formula:
\[ \text{Number of neutrons} = A - Z \]
- Substituting the values we have:
\[ \text{Number of neutrons} = 27 - 13 = 14 \]

### Step 4: Determine the number of electrons
- In a neutral atom, the number of electrons equals the number of protons.
- Therefore, the number of electrons in Aluminum-27 is:
\[ \text{Number of electrons} = \text{Number of protons} = 13 \]

### Final Summary
- Number of protons: 13
- Number of neutrons: 14
- Number of electrons: 13