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50% of a radio active substance decays i...

`50%` of a radio active substance decays in `5` hours. The time required for the `87.5%` decays is

A

`10` hours

B

`15` hours

C

`12.5` hours

D

`17.5` hours

Text Solution

Verified by Experts

The correct Answer is:
B
`W=(W_(0))/(2^(n)) n=(t)/(t_((1)/(2))), t_(1//2)= 5 hrs`
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