`4` grams of radioactive substance `A` left `1//2 gm` after some ture. `1` gran of another radioactive substance `B` left `1//4 gm` in the same period, If half life of `B` is `2` hours, the half life of `A` is ( in hours)

Options

A. `3//4`
B. `4//3`
C. `1//4`
D. `1//2`

Answer

B

Explanation

`W=(W_(0))/(2^(n))`, no of half lives `n=(t)/(t_(1//2))`