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A radioactive isotope is being produced ...

A radioactive isotope is being produced at a constant rate `dN//dt=R` in an experiment. The isotope has a half-life `t_(1//2)`.Show that after a time `t gtgt t_(1//2)`,the number of active nuclei will become constant. Find the value of this constant.

A

`AT`

B

`(A)/(T) ln`

C

`AT ln`

D

`(AT)/(ln(2))`

Text Solution

Verified by Experts

The correct Answer is:
D
`A=N lambda, :.N=(A)/(lambda)=(AT)/(In2)`
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