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The isotope (5)^(12) B having a mass 12....

The isotope `_(5)^(12) B` having a mass `12.014 u`undergoes beta - decay to `_(6)^(12) C _(6)^(12) C `has an excited state of the nucleus `( _(6)^(12) C ^(**) at 4.041 MeV` above its ground state if `_(5)^(12)E` decay to `_(6)^(12) C ^(**) ` , the maximum kinetic energy of the `beta` - particle in unit of MeV is `(1 u = 931.5MeV//c^(2)` where c is the speed of light in vaccuum) .

Text Solution

Verified by Experts

Q value `=[12.014u-(12u+4.041(MeV)/(c^(2)))]c^(2)`
`Q=(0.014uxx931.5)MeV-(4.041)MeV=9 MeV`
Hence, `beta` particle will have a maximum KE of `9 MeV`.
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The isotope _(5)^(12) B having a mass 12.014 u undergoes beta - decay to _(6)^(12) C _(6)^(12) C has an excited state of the nucleus ( _(6)^(12) C ^(**) at 4.041 MeV above its ground state if _(5)^(12)E decay to _(6)^(12) C ^(**) , the maximum kinetic energy of the beta - particle in unit of MeV is (1 u = 931.5MeV//c^(2) where is the speed of light in vacume ) .

.^(12)N beta decays to an ecited state of .^(12)C , which subsequenctly decays to the ground state with the emission of a 4.43 -MeV gamma ray. What is the maxium kinetic energy of the emitted beta particle?

Knowledge Check

  • The oxidation state of C in C_(6)H_(12)O_(6) is -

    A
    `+1`
    B
    `+2`
    C
    0
    D
    None

  • ""_(6)^(12) C absorbs an energetic neutron and emits a beta - particle . The resulting nucleus is

    A
    `""_(7)^(14)N`
    B
    `""_(7)^(13) N`
    C
    `""_(7)^(13) B`
    D
    `""_(6)^(13) C `

  • Number of atoms in 12 g of ""_(6)^(12) C is :

    A
    6
    B
    12
    C
    `6.022 xx 10^(23)`
    D
    `12 xx 6.022 xx 10^(23)`

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    Calculate the maximum kinetic energy of the bera particle emitted in the following decay scheme: ^12N rarr 12C **+e^(+)+v ^12C rarr ^12C + gamma(4.43 MeV). The atomic mass of 12N is 12.018612 u.

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