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A nuclear of mass M +deltam is at rest ...

A nuclear of mass `M +deltam ` is at rest and decay into two daughter nuclei of equal mass `(M)/(2)` each speed is `c`
The speed of daughter nuclei is

A

`c(Delta m)/(M+Delta m)`

B

`csqrt((2 Delta m)/(M))`

C

`csqrt(( Delta m)/(M))`

D

`csqrt((Delta m)/(M+Delta m))`

Text Solution

Verified by Experts

According to conservation of momentum
`0 = (M)/(2) V_(1) - (M)/(2)V_(2), V_(1) = V_(2)`,
`Deltamc^(2) = (1)/(2) (M)/(2) V_(1)^(2) + (1)/(2).(M)/(2) V_(2)^(2)`
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