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The electrical conductivity of a semicon...

The electrical conductivity of a semiconductor increases when electromagnatic radiation of wavelength shorter than 2480 nm is incident on it. The band gap (in eV) for the semiconductor is `[hc=1242 eV nm]`

A

`0.7 eV`

B

`0.5 eV`

C

`2.5 eV`

D

`1.2 eV`

Text Solution

Verified by Experts

The correct Answer is:
B
`E_(g)=(hc)/(lamda)=(6.6 xx10^(-34) xx 3 xx 10^(8))/(2480 xx10^(-9) xx(1.6 xx10^(-19)))`
`=0.5 eV`.
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