The reverse bias in a junction diode is changed from `5V` to `15 V` then the value of current changes from `38 mu A` to `88 mu A`. The resistance of junction diode will be.

Options

A. `4 xx 10^(5) Omega`
B. `3 xx 10^(5) Omega`
C. `2 xx 10^(5) Omega`
D. `10^(6) Omega`

Answer

C

Explanation

`R =(Delta V)/(Delta I) =(15-5)/((88-38) xx 10^(-6)) =(10)/(50 xx 10^(-6))`
`=(10^(6))/(5) =(10)/(5) xx 10^(5) = 2 xx 10^(5) Omega`.