For a `CE`-transistor amplifier, the audio signal voltage across the collector resistance of `2k Omega` is `2V`. Suppose the current amplification factor of the transistor is `100`. Find the input signal voltage and base current, if the base resistance is `1 k Omega`.

Options

A. `0.02 V`
B. `0.01 V`
C. `0.03 V`
D. `0.04 V`

Answer

B

Explanation

Here : `v_(0) = 2V, beta = 100`,
`R_(C)` (collector resistance) `= 2kOmega, R_(B) = 1 k Omega`
As `A_(v)=(v_(0))/(v_(1))=beta((R_(C))/(R_(B))),v_(i)=v_(0)((R_(B))/(R_(C)))((1)/(beta))`
`=(2V)((1kOmega)/(2kOmega))((1)/(100))=0.01V`.