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The following data are for intrinsic ger...

The following data are for intrinsic germanium at `300 K. n_(i) = 2.4 xx 10^(19)//m^(3), mu_(e) = 0.39 m^(2)//Vs, mu_(h) = 0.19 m^(2)//Vs`. Calculate the coductivity of intrinsic germanium.

A

`4.3 Sm^(-1)`

B

`1.21 Sm^(-1)`

C

`2.22 Sm^(-1)`

D

`4.22 Sm^(-1)`

Text Solution

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The correct Answer is:
To calculate the conductivity of intrinsic germanium at 300 K, we can follow these steps: ### Step 1: Understand the Formula for Conductivity The conductivity (\( \sigma \)) of a semiconductor can be expressed as the sum of the contributions from electrons and holes: \[ \sigma = \sigma_e + \sigma_h \] where: - \( \sigma_e = n_e \cdot \mu_e \cdot e \) (conductivity due to electrons) - \( \sigma_h = n_h \cdot \mu_h \cdot e \) (conductivity due to holes) ### Step 2: Identify the Parameters For intrinsic germanium, the concentration of electrons (\( n_e \)) is equal to the concentration of holes (\( n_h \)), which is equal to the intrinsic carrier concentration (\( n_i \)): \[ n_e = n_h = n_i = 2.4 \times 10^{19} \, \text{m}^{-3} \] The mobilities are given as: - \( \mu_e = 0.39 \, \text{m}^2/\text{Vs} \) - \( \mu_h = 0.19 \, \text{m}^2/\text{Vs} \) The charge of an electron (or hole) is: \[ e = 1.6 \times 10^{-19} \, \text{C} \] ### Step 3: Substitute Values into the Formula Now we can substitute the values into the formula for conductivity: \[ \sigma = n_i \cdot \mu_e \cdot e + n_i \cdot \mu_h \cdot e \] Factoring out \( n_i \cdot e \): \[ \sigma = n_i \cdot e \cdot (\mu_e + \mu_h) \] ### Step 4: Calculate the Total Mobility Calculate the total mobility: \[ \mu_e + \mu_h = 0.39 + 0.19 = 0.58 \, \text{m}^2/\text{Vs} \] ### Step 5: Substitute All Values into the Conductivity Formula Now substitute all values into the conductivity formula: \[ \sigma = (2.4 \times 10^{19}) \cdot (1.6 \times 10^{-19}) \cdot (0.58) \] ### Step 6: Perform the Calculation Calculating the above expression: \[ \sigma = 2.4 \times 1.6 \times 0.58 \] Calculating step by step: 1. \( 2.4 \times 1.6 = 3.84 \) 2. \( 3.84 \times 0.58 = 2.2272 \) Thus, the conductivity is: \[ \sigma \approx 2.22 \, \text{S/m} \] ### Final Answer The conductivity of intrinsic germanium at 300 K is approximately: \[ \sigma \approx 2.22 \, \text{S/m} \]

To calculate the conductivity of intrinsic germanium at 300 K, we can follow these steps: ### Step 1: Understand the Formula for Conductivity The conductivity (\( \sigma \)) of a semiconductor can be expressed as the sum of the contributions from electrons and holes: \[ \sigma = \sigma_e + \sigma_h \] where: ...
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