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For a transistor x=(1)/(alpha)&y=(1)/(be...

For a transistor `x=(1)/(alpha)&y=(1)/(beta)` where `alpha & beta` are current gains in common base and common emitter configuration. Then

A

`x+y =1`

B

`x -y =1`

C

`2x =1 - y`

D

`x+y =0`

Text Solution

Verified by Experts

The correct Answer is:
B
`alpha -(Delta I_(c))/(Delta I_(e)), beta =(Delta I_(c))/(Delta I_(b))`.
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