A CE amplifier is designed with a transi...

A `CE` amplifier is designed with a transistor having `alpha =0.99`. Input impedance is `1 k Omega` and load is `10 k Omega`. Voltage gain will be :

`9900`

`99000`

`99`

`990`

Text Solution

Verified by Experts

The correct Answer is:

`beta =(alpha)/(1-alpha)` and `A_(v)=beta xx(R_(AC))/(R_("in"))`.

Topper's Solved these Questions

SEMI CONDUCTOR DEVICES
NARAYNA|Exercise Level-I (H.W)|26 Videos
RAY OPTICS AND OPTICAL INSTRAUMENTS
NARAYNA|Exercise EXERCISE- 4 One or more than one correct answer type|13 Videos
SEMICONDUCTOR ELECTRONICS
NARAYNA|Exercise ADDITIONAL EXERCISE (ASSERTION AND REASON TYPE QUESTIONS :)|19 Videos

Similar Questions

Explore conceptually related problems

A common emitter amplifier is designed with NPN transistor (alpha = 0.99) . The input impedance is 1 K Omega and load is 10 K Omega . The voltage gain will be

A common-emitter amplifier is designed with an n-p-n transistor (alpha=0.99) .The input impedance is 1kOmega and the load is 10kOmega .The voltage gain will be

A common emitter amplifier is designed with NPN transistor (alpha=0.99) . The input impedence is 1k Komega and load is 10 Komega . The voltage gain will be

A common emitter amplifier is designed with n-p-n transistor (alpha=0.99) . The input resistance is 1K ohm and load is 10 k ohm . The voltage gain will be

The current gain in the CE mode of a transistor is 10. If the input impedance is 10 K Omega and load resistance = 60 K Omega , then the power gain will be

The current gain in the common emitter mode of a transistor is 10. The input impedance is 20kOmega and load of resistance is 100k Omega . The power gain is

A common emitter amplifier has current gain 70. Its load resistance is 5 k Omega and input resistance is 500 Omega . The voltage gain is

An npn transistor operates as a common emitter amplifier with a power gain of 10^6 . The input circuit resistance is 100 Omega and the output load resistance is 10 k Omega . The common emitter current gain ' beta ' will be (Round off to the Nearest Integer)

NARAYNA-SEMI CONDUCTOR DEVICES-Level-II (H.W)

Current amplification factor of a common base configuration is 0.88. F...
Text Solution
|
For a transistor beta = 40 and I(B) = 25 muA. Find the value of I(E).
Text Solution
|
In a transistor if (I(C))/(I(E))=alpha and (I(C))/(I(B))=beta,If alpha...
Text Solution
|
For a transistor x=(1)/(alpha)&y=(1)/(beta) where alpha & beta are cur...
Text Solution
|
A voltage amplifier operated from a 12 volt battery has a collector lo...
Text Solution
|
A CE amplifier is designed with a transistor having alpha =0.99. Input...
Text Solution
|
In a common emitter amplifier the load resistance of the output circui...
Text Solution
|
In a transistor amplifier beta = 62, R(L) = 5000 Omega and internal re...
Text Solution
|
The tuned collector oscillator circuit used in the local oscillator of...
Text Solution
|
When we add binary number 111 and 111 we get the binary number :
Text Solution
|
If A =B=C=1 and X= overline(ABC)+B overline(BC) + C overline(AB), then...
Text Solution
|
The input of A and Bfor the Boolean expression (overline(A+B)).(overli...
Text Solution
|
Write the truth table for the circuit shown in figure given below. Nam...
Text Solution
|
Consider a two-input AND gate of figure below. Out of the four entries...
Text Solution
|
A Truth table is given below. The below. The logic gate having followi...
Text Solution
|
For a logic 0101 the waveform is.
Text Solution
|
For the given combination of gates, if the logic states of inputs A,B,...
Text Solution
|
Identify the gate represented by the block diagram as shown in fig.
Text Solution
|
The Boolean expression for the gate circuit shown below is
Text Solution
|
The output Y of the gate circuit shown in the figure below is
Text Solution
|