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In a transistor amplifier beta = 62, R(L...

In a transistor amplifier `beta = 62, R_(L) = 5000 Omega` and internal resistance of the transistor is `500 Omega`. Its power amplification will be.

A

`25580`

B

`33760`

C

`38440`

D

`55760`

Text Solution

Verified by Experts

The correct Answer is:
C
`A_(P)=beta^(2)(R_(L))/(R_(i))`.
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Knowledge Check

  • In a transistor amplifier, beta=62,R_(L)=5000Omega and input resistance of the transistor is 500 Omega . What is the power amplification?

    A
    6200
    B
    45850
    C
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    D
    15320

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    A
    500
    B
    460
    C
    600
    D
    560

  • In a common emitter transistor amplifier, beta=60, R_(0)=5000Omega and internal resistance of a transistor is 500Omega . The voltage amplification of the amplifier will be

    A
    500
    B
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    C
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    D
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