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In a transistor amplifier beta = 62, R(L...

In a transistor amplifier `beta = 62, R_(L) = 5000 Omega` and internal resistance of the transistor is `500 Omega`. Its power amplification will be.

A

`25580`

B

`33760`

C

`38440`

D

`55760`

Text Solution

Verified by Experts

The correct Answer is:
C
`A_(P)=beta^(2)(R_(L))/(R_(i))`.
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