Constant as eliptical rail `PQ` in the varticle plain with `OP = = 3m ` and `OQ= 4 m` . A block of mass `1` kg is pailed along the rail from `P` to `Q` with a force of `18 N` , which is always parallel to less `PQ` Assuming are frictionless losess , the kinetic energy the block when `0` reches `Q` is `( nxx 10)` pales . THe velie of a (Take acceleration due to gravity ) `= 10ms^(-2))`

Consider an elliptically shaped rail PQ in the vertical plane with OP = 3 m and OQ = 4 m. A block of mass 1 kg is pulled along the rail from P to Q with a force of 18 N, which is always parallel to line PQ (see the figure given). Assuming no frictional losses, the kinetic energy of the block when it reaches Q is: (n xx 10) joules. The value of n is (take acceleration due to gravity = 10 ms^(-2) ) https://haygot.s3.amazonaws.com/questions/113759.jpg

A block of mass 5 kg is initially at rest on a rough horizontal surface. A force of 45 N acts over a distance of 2 m . The force of friction acting on the block is 25 N . The final kinetic energy of the block is

A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. If a force P is applied at the free end of the rope, the force exerted by the rope on the block will be

A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m . Force P is applied at one end of rope. The force which the rope exerts on the block is:

A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m . Force P is applied at one end of rope. The force which the rope exerts on the block is:

A block of mass 2 kg is pulled through 3 m by a constnat horizontal force of 10N, along a frictionless horizontal table. What is the work doen by (i) the applied force and (ii) the gravitational force?

A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. If a force P is applied at the free end of the rope, the force exerted by the rope on the block is