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Light waves form two coherent source having internsity ration `81:1` produce interference. Then, the ratio of maxima and minima in the interference pattern will be

Text Solution

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Given, `(I_(1))/(I_(2))=(A_(1)^(2))/(A_(2)^(2))=(81)/(1)`
`:. (A_(1))/(A_(2))=(9)/(1)` or `A_(1)=9 A_(2)` …….(1)
`:. (I_(max))/(I_(min))=((A_(1)+A_(2))^(2))/((A_(1)-A_(2))^(2))`
" From Eq. " (i), we get
`(I_(max))/(I_("min"))= ((9A_(2)+A_(2))^(2))/((9A_(2)-A_(2))^(2)) = ((10)^(2))/((8)^(2)) =(25)/(16)`
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Knowledge Check

  • Two coherent sources of intensities I_1 and I_2 produce an interference pattern. The maximum intensity in the interference pattern will be

    A
    (a) `I_1+I_2`
    B
    (b) `I_1^2+I_2^2`
    C
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    D
    (d) `(sqrt(I_1)+sqrt(I_2))^2`
  • Interference fringes are obtained due to interference of waves from two coherent sources of light having amplitude a_1 and 2a_1 . The ratio of maximum and minimum intensities in the interference pattern will be

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    2
    B
    3
    C
    4
    D
    9
  • Two waves having intensities in the ratio of 16:1 produce interference. The ratio of maxium to minimum intensities is equal to

    A
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    B
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    D
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