Two slits are one millimeter apart and the screen is placed one meter away. What should the width of each slit be to obtain 10 maxima of the double slit pattern within the central maximum of the single pattern.

Explanation

We have `a theta=lambda (or) theta= (lambda)/(a)`
(a = width of each slit)
`10 (lambda)/(d)= 2(lambda)/(a)`
`:. a= (d)/(5) = (1)/(5)= 0.2 mm`